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An Engineer has to develop a triangular shaped park with a perimeter 120 m in a village. The park to be developed must be of maximum area. Find out the dimensions of the park - Mathematics

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प्रश्न

An Engineer has to develop a triangular shaped park with a perimeter 120 m in a village. The park to be developed must be of maximum area. Find out the dimensions of the park

बेरीज

उत्तर

Let ∆ABC be the triangular-shaped park.

a, b, c be the length of the sides.

Given perimeter of the park = 120 m

2s = a + b + c = 120 m   ......(1)

For a fixed perimeter 2s.

The area of a triangle is maximum when a = b = c.

(1) = a + a + a = 120

3a = 120

⇒ a = 40 m

Length of the sides 40 m, 40 m, 40 rn.

Maximum area ∆ = `8^2/(3sqrt(3))`

= `60^2/(3sqrt(3))`

= `(60 xx 60)/(3sqrt(3))`

= `(20 xx 20 xx 3)/sqrt(3)`

= `40sqrt(3)` sq.m.

shaalaa.com
Properties of Triangle
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometry - Exercise 3.9 [पृष्ठ १४३]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 3 Trigonometry
Exercise 3.9 | Q 9 | पृष्ठ १४३

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