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प्रश्न
An image formed by a lens is erect. Such an image could be formed by a
पर्याय
the convex lens provided the image is smaller than an object.
the concave lens provided the image is smaller than an object.
the concave lens provided the image is larger than an object.
the concave lens provided the image is of the same size.
उत्तर
the concave lens provided the image is smaller than an object.
Explanation:
A concave lens provided the image is smaller than an object. The image of an object created by a concave lens is erect, virtual, and diminished.
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संबंधित प्रश्न
Which mirror is used as a torch reflector? Draw a labelled diagram to show how a torch reflector can be used to produce a parallel beam of light. Where is the bulb placed in relation to the torch reflector?
Make labelled ray diagrams to illustrate the formation of:
a virtual image by a converging mirror.
Mark clearly the pole, focus, centre of curvature and position of object in each case.
Briefly describe how you would find the focal length of a concave mirror quickly but approximately
An object is 100 mm in front of a concave mirror which produces an upright (erect image). The radius of curvature of the mirror is ______.
An object is placed at a distance of 10 cm from a concave mirror of focal length 20 cm.
Calculate the image distance.
Which of the following are concave mirrors and which convex mirrors?
An object is placed 15 cm from (a) a converging mirror, and (b) a diverging mirror, of radius of curvature 20 cm. Calculate the image position and magnification in each case.
A student determines the focal length of a device 'X' by focusing the image of a distant object on a screen placed 20 cm from the device on the same side as the object. The device 'X' is
(a) Concave lens of focal length 10 cm
(b) Convex lens of focal length 20 cm
(c) Concave mirror of focal length 10 cm
(d) Concave mirror of focal length 20 cm
State whether true or false. If false, correct the statement.
When an object is at the centre of curvature of concave mirror the image formed will be virtual and erect.
Rays from Sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of its image is equal to the size of the object?
