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प्रश्न
Area of a triangle = `1/2` base × ______.
उत्तर
Area of a triangle = `1/2` base × height.
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संबंधित प्रश्न
Prove that the points (2,3), (-4, -6) and (1, 3/2) do not form a triangle.
Find the value of x for which points A(x, 2), B(-3, -4) and C(7, -5) are collinear.
Find the value of y for which the points A(-3, 9), B(2,y) and C(4,-5) are collinear.
If the points P(-3, 9), Q(a, b) and R(4, -5) are collinear and a+b=1, find the value of a and b.
The coordinates of the point P dividing the line segment joining the points A (1, 3) and B (4, 6) in the ratio 2 : 1 are:
In Figure 1, PS = 3 cm, QS = 4 cm, ∠PRQ = θ, ∠PSQ = 90°, PQ ⊥ RQ and RQ = 9 cm. Evaluate tan θ.
Using integration, find the area of triangle ABC, whose vertices are A(2, 5), B(4, 7) and C(6, 2).
In ∆PQR, PR = 8 cm, QR = 4 cm and PL = 5 cm. 
Find:
(i) the area of the ∆PQR
(ii) QM.
The area of a triangle with vertices (a, b + c), (b, c + a) and (c, a + b) is ______.
Find the missing value:
| Base | Height | Area of Triangle |
| 22 cm | ______ | 170.5 cm2 |
