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प्रश्न
Construct a combined histogram and frequency polygon for the following frequency distribution:
| Class-Intervals | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 |
| Frequency | 3 | 5 | 6 | 4 | 2 |
उत्तर
Steps:
1. Draw a histogram for the given data.
2. Mark the mid-point at the top of each rectangle of the histogram drawn.
3. Also, mark the mid-point of the immediately lower class-interval and mid-point of the immediately higher class-interval.
4. Join the consecutive mid-point marked by straight lines to obtain the required frequency polygon.
5. The require combined histogram and frequency polygon are shown in the following figure:
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(i) What is the information given by the bar graph?
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(iii) Of which state, were the maximum number of tickets sold?
(iv) State whether true or false.
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(ii) In which year the export is minimum?
(iii)In which year the import is maximum?
(iv)In which year the difference of the values of export and import is maximum?
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| Production (In thousand tonnes) |
160 | 80 | 200 | 150 |
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| Income (Rs. inthousands) |
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Represent the above data by a gar graph.
The distribution of heights (in cm) of 96 children is given below. Construct a histogram and a frequency polygon on the same axes.
| Height (in cm): | 124 to 128 |
128 to 132 |
132 to 136 |
136 to 140 |
140 to 144 |
144 to 148 |
148 to 152 |
152 to 156 |
156 to 160 |
160 to 164 |
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In a frequency distribution, ogives are graphical representation of
In a histogram the area of each rectangle is proportional to
A histogram is a pictorial representation of the grouped data in which class intervals and frequency are respectively taken along
Following table shows a frequency distribution for the speed of cars passing through at a particular spot on a high way:
| Class interval (km/h) | Frequency |
| 30 – 40 | 3 |
| 40 – 50 | 6 |
| 50 – 60 | 25 |
| 60 – 70 | 65 |
| 70 – 80 | 50 |
| 80 – 90 | 28 |
| 90 – 100 | 14 |
Draw the frequency polygon representing the above data without drawing the histogram.
