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प्रश्न
Construct a triangle similar to ΔABC in which AB = 4.6 cm, BC = 5.1 cm, ∠A = 60° with scale factor 4 : 5.
उत्तर
Given that
Construct a ΔABC of given data, AB = 4.6 cm, BC = 5.1 cm, ∠A = 60° and then a triangle similar to it whose sides are (4.5 = 4/5)th of the corresponding sides of ΔABC.
We follow the following steps to construct the given
Step of construction
Step: I- First of all we draw a line segment AB = 4.6 cm.
Step: II- With A as centre draw an angle ∠A = 60°.
Step: III- With B as centre and radius = BC = 5.1 cm, draw an arc, intersecting the arc drawn in step II at C.
Step: IV- Joins BC to obtain ΔABC.
Step: V- Below AB, makes an acute angle ∠BAX = 60°.
Step: VI- Along AX, mark off five points A1, A2, A3, A4 and A5 such that AA1 = A1A2 = A2A3 = A3A4 = A4A5
Step: VII- Join A5B.
Step: VIII- Since we have to construct a triangle each of whose sides is (4/5)th of the corresponding sides of ΔABC.
So, we take four parts out of five equal parts on AX from point A4 draw A4B' || A5B, and meeting AB at B’.
Step: IX- From B’ draw B'C' || BC and meeting AC at C’
Thus, ΔAB'C' is the required triangle, each of whose sides is (4/5)th of the corresponding sides of ΔABC.
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संबंधित प्रश्न
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Solution:
Point P divides segment AB in the ratio m: n.
A(8, 9) = (x1, y1), B(1, 2 ) = (x2, y2) and P(6, 7) = (x, y)
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