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[Cr(NH3)6]3+ is paramagnetic while [Ni(CN)4]2− is diamagnetic. Explain why? - Chemistry

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प्रश्न

[Cr(NH3)6]3+ is paramagnetic while [Ni(CN)4]2− is diamagnetic. Explain why?

स्पष्ट करा

उत्तर

Formation of [Cr(NH3)6]3+: The oxidation state of chromium in [Cr(NH3)6]3+ ion is +3. The electronic configuration of chromium is [Ar] 3d54s1. The hybridisation is shown in the following diagram –

The Cr3+ ion provides six vacant orbitals to accommodate six electron pairs from six ammonia molecules. As a result, the complex [Cr(NH3)6]3+ has d2sp3 hybridisation and is octahedral. The presence of three unpaired electrons in the complex explains its paramagnetic property.

Formation of [Ni(CN)4]2−In [Ni(CN)4]2− the oxidation state of Ni is +2 and its electronic configuration is 3d. Hybridisation can be explained as follows –

Each hybridised orbital accepts a pair of electrons from the cyanide ion. The absence of unpaired electrons confirms the diamagnetic behaviour of [Ni(CN)4]2−.

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पाठ 9: Coordinate Compounds - Exercises [पृष्ठ २५९]

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एनसीईआरटी Chemistry [English] Class 12
पाठ 9 Coordinate Compounds
Exercises | Q 19 | पृष्ठ २५९

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