Advertisements
Advertisements
प्रश्न
Determine the value of m, if (x + 3) is a factor of x3 – 3x2 – mx + 24
उत्तर
p(x) = x3 – 3x2 – mx + 24
when x + 3 is a factor
P(–3) = 0
(–3)3 – 3(–3)2 – m(–3) + 24 = 0
– 27 – 27 + 3m + 24 = 0
– 54 + 24 + 3m = 0
– 30 + 3m = 0
3m = 30
m = `30/3`
= 10
The value of m = 10
APPEARS IN
संबंधित प्रश्न
Find the value of k, if 3x – 4 is a factor of expression 3x2 + 2x − k.
Find the values of m and n so that x – 1 and x + 2 both are factors of x3 + (3m + 1)x2 + nx – 18.
Using the Factor Theorem, show that (3x + 2) is a factor of 3x3 + 2x2 – 3x – 2. Hence, factorise the expression 3x3 + 2x2 – 3x – 2 completely.
Using the Remainder Theorem, factorise each of the following completely.
3x3 + 2x2 – 23x – 30
Prove by factor theorem that
(3x-2) is a factor of 18x3 - 3x2 + 6x -12
Prove that (x-3) is a factor of x3 - x2 - 9x +9 and hence factorize it completely.
Find the value of the constant a and b, if (x – 2) and (x + 3) are both factors of expression x3 + ax2 + bx - 12.
Use factor theorem to factorise the following polynominals completely.
x3 + 2x2 – 5x – 6
If x – 2 is a factor of x3 – kx – 12, then the value of k is ______.
If x – 3 is a factor of x2 + kx + 15; the value of k is ______.