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प्रश्न
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[FeF6]3−
उत्तर
In this complex, the oxidation state of Fe is +3.
Orbitals of Fe+3 ion:
There are 6 F− ions. Thus, it will undergo d2sp3 or sp3d2 hybridization. As F− is a weak field ligand, it does not cause the pairing of the electrons in the 3d orbital. Hence, the most feasible hybridization is sp3d2.
sp3d2 hybridized orbitals of Fe are:
Hence, the geometry of the complex is found to be octahedral.
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संबंधित प्रश्न
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[Fe(CN)6]4−
Explain the geometry of `[Co(NH_3)_6]^(3+)` on the basis of hybridisation. (Z of Co = 27)
Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[Mn(CN)6]^{3-}}\]
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[Co(NH3)6]^{3+}}\]
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
The type of hybridization involved in Octahedral complexes is ______.
Write the hybridization and shape of the following complexes:
[Ni(CN)4]2−
If orbital quantum number (l) has values 0, 1, 2 and 3, deduce the corresponding value of principal quantum number, n.
Which of the statement given below is incorrect about H2O2?
Which of the following methods is used for measuring bond length?
What is the no. of possible isomers for the octahedral complex [Co(NH3)2(C2O4)2]?
In Fe(CO)5, the Fe – C bond possesses
Valence bond theory is based on the assumption that the bonds formed between the metal ions and ligands are ______
Using valence bond theory, predict the hybridization and magnetic character of the following:
[CoF6]3– [Atomic number of Co = 27]
Write the hybridisation and magnetic behaviour of [CoF6]3−.
[Given: Atomic number of Co = 27]
[Ni(CO)4] has tetrahedral geometry while [Ni(CN)4]2− has square planar, yet both exhibit diamagnetism. Explain.
[Atomic number: Ni = 28]
