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प्रश्न
Draw a line segment AB = 5.5 cm. Mark a point P, such that PA = 6 cm and PB = 4.8 cm. From point P, draw a perpendicular to AB.
उत्तर
Step of Construction :
- Draw a line segment AB = 5.5 cm
- With A as centre and radius = 6 cm, draw an arc.
- With B as centre and radius = 4.8 cm draw another arc.
- Let these arcs meet each other at point P.
PA = 6 cm, PB = 4.8 - With P as a centre and some suitable radius draw an arc meeting AB at points C and D.
- With C as centre and radius more than half of CD, draw an arc.
- With D as a centre and same radius as in step 6, draw an arc.
- Let these arcs meet each other at point Q.
- Join PQ.
- The PQ meet AB at point O.
Then PO ⊥ AB i.e; ∠AOP = 90° = ∠POB.
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संबंधित प्रश्न
In each of the following, draw perpendicular through point P to the line segment AB :
(i)
(ii)
(iii)
Draw a line segment AB of length 5.5 cm. Bisect it using a compass and ruler.
Infinitely many perpendicular bisectors can be drawn to a given ray.
Draw an angle of 140° with the help of a protractor and bisect it using ruler and compasses.
Copy figure on your notebook and draw a perpendicular to l through P, using (i) set squares (ii) protractor (iii) ruler and compass. How many such perpendiculars are you able to draw?
Draw a line segment of length 6 cm. Construct its perpendicular bisector. Measure the two parts of theline segment.
Draw a line segment of length 10 cm. Divide it into four equal parts. Measure each of these parts.
Draw a circle with centre C and radius 3.4 cm. Draw any chord `overline"AB"`. Construct the perpendicular bisector of `overline"AB"` and examine if it passes through C.
Draw a circle of radius 4 cm. Draw any two of its chords. Construct the perpendicular bisectors of these chords. Where do they meet?
Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of `overline"OA"` and `overline"OB"`. Let them meet at P. Is PA = PB ?
