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प्रश्न
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
7 cm
उत्तर
Construction:
Step 1: Drawn a line and marked points A and B on it so that AB = 7 cm.
Step 2: Using compass with A as centre and radius more than half of the length of AB drawn two arcs of same length one above AB and one below AB.
Step 3: With the same radius and B as centre drawn two arcs to cut the already drawn arcs in step 2.
Marked the intersection of the arcs as C and D
Step 4: Joined C and D, CD is the required perpendicular bisector of AB.
AO = OB
= `7/2`
= 3.5 cm, ∠AOC = 90°
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संबंधित प्रश्न
Draw a line segment PQ = 4.8 cm. Construct the perpendicular bisector of PQ.
It is possible to draw two bisectors of a given angle.
In figure, the point C is the image of point A in line l and line segment BC intersects the line l at P.
(a) Is the image of P in line l the point P itself?
(b) Is PA = PC?
(c) Is PA + PB = PC + PB?
(d) Is P that point on line l from which the sum of the distances of points A and B is minimum?
Copy figure on your notebook and draw a perpendicular from P to line m using (i) set squares (ii) protractor (iii) ruler and compass. How many such perpendicular are you able to draw?
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Draw the perpendicular bisector of `overline"XY"` whose length is 10.3 cm.
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-
If M is the midpoint of `overline"XY"`, what can you say about the lengths MX and XY?
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