Advertisements
Advertisements
प्रश्न
Draw the graph of the equation given below. Also, find the coordinates of the point
where the graph cuts the coordinate axes : −x + 4y = 8
उत्तर
We have
−x + 4y = 8
⇒ 4y - 8 = x
⇒ x = 4y = 8
Putting y = 1 in (1) , we get x = 4 × 1 - 8 = -4
Putting y = 2 in (1) , we get x = 4 × 2 - 8 = 0
Thus, we obtain the following table giving coordinates of two points on the line
represented by the equation - x + 4 y = - 8
Graph of the equation - x + 4 y = - 8
APPEARS IN
संबंधित प्रश्न
Draw the graph of the following linear equation in two variable : –x + y = 6
Draw the graph of y = | x |.
Draw the graph for the equation given below; hence find the co-ordinates of the points where the graph is drawn meets the co-ordinates axes:
`(2x + 15)/(3) = y - 1`
Draw the graph of the equation
4x + 3y + 6 = 0
From the graph, find :
(i) y1, the value of y, when x = 12.
(ii) y2, the value of y, when x = - 6.
Use the graphical method to find the value of k, if:
(k, -3) lies on the straight line 2x + 3y = 1
Solve, graphically, the following pairs of equation :
3x + 7y = 27
8 - y = `(5)/(2)x`
Draw the graph for the following
3x + 2y = 14
The graph of the linear equation y = x passes through the point ______.
Every point on the graph of a linear equation in two variables does not represent a solution of the linear equation.
Write the linear equation such that each point on its graph has an ordinate 3 times its abscissa.
