Advertisements
Advertisements
प्रश्न
Draw the graph of the equation
4x + 3y + 6 = 0
From the graph, find :
(i) y1, the value of y, when x = 12.
(ii) y2, the value of y, when x = - 6.
उत्तर
4x + 3y + 6 = 0
⇒ 3y = -4x - 6
⇒ y = `(-4x - 6)/(3)`
When x = 0,
y = `(-4(0)-6)/(3)`
= `(-6)/(3)`
= -2
When x = 3,
y = `(-4(3)-6)/(3)`
= `(-12 -6)/(3)`
= -6
When x = -3,
y = `(-4(3)-6)/(3)`
= `(12 -6)/(3)`
= 2
| X | 0 | 3 | -3 |
| Y | -2 | -6 | 2 |
Plotting these points we get the required graph as shown below:
The value of y, when x = 12:
We have the equation of the line as
y = `(- 4x - 6)/3`
Now substitute x = 12 and y = y1:
y1 = `(-4(12)-6)/(3)`
= `(-48 - 6)/(3)`
= `(-54)/(3)`
= - 18
The value of y, when x = - 6:
Now substitute x = - 6 and y = y2:
y2 = `(-4(-6)-6)/(3)`
= `(24 - 6)/(3)`
= `(18)/(3)`
= 6
APPEARS IN
संबंधित प्रश्न
If the work done by a body on application of a constant force is directly proportional to the distance travelled by the body, express this in the form of an equation in two variables and draw the graph of the same by taking the constant force as 5 units. Also read from the graph the work done when the distance travelled by the body is
(i) 2 units (ii) 0 unit
From the choices given below, choose the equation whose graph is given in Fig. below.
(i) y = x (ii) x + y = 0 (iii) y = 2x (iv) 2 + 3y = 7x
[Hint: Clearly, (-1, 1) and (1, -1) satisfy the equation x + y = 0]
Draw the graph of the equation given below. Also, find the coordinates of the point
where the graph cuts the coordinate axes : −x + 4y = 8
Draw the graph for the equation, given below :
x + 5 = 0
Draw the graph for the equation, given below :
5x + y + 5 = 0
Use the graphical method to find the value of k, if:
(5, k - 2) lies on the straight line x - 2y + 1 = 0
Draw the graph for the following
y = 2x
Find the values.
y = x + 3
| x | 0 | − 2 | ||
| y | 0 | − 3 |
Find the values.
y = 3x + 1
| x | − 1 | 0 | 1 | 2 |
| y |
The graph of the linear equation 2x + 3y = 6 cuts the y-axis at the point ______.
