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प्रश्न
Draw the graph for the equation given below; hence find the co-ordinates of the points where the graph is drawn meets the co-ordinates axes:
`(2x + 15)/(3) = y - 1`
उत्तर
`(2x + 15)/(3) = y - 1`
⇒ 2x + 15 = 3(y - 1)
⇒ 2x + 15 = 3y - 3
⇒ 2x - 3y = -15 - 3
⇒ 2x - 3y = -18
⇒ -3y = -18 - 2x
⇒ y = `(-18 - 2x)/(-3)`
When x = 0,
y = `(-18-[2 xx 0])/(-3)`
= `(-18 -0)/(-3)`
= 6
When x = -3,
y = `(-18-[2 xx (-3)])/(-3)`
= `(-18 + 6)/(-3)`
= 4
When x = -6,
y = `(-18-[2 xx (-6)])/(-3)`
= `(-18 + 12)/(-3)`
= 2
| X | 0 | - 3 | - 6 |
| Y | 6 | 4 | 2 |
Plotting these points we get the required graph as shown below:
From the figure it is clear that, the graph meets the coordinate axes at (-9, 0) and (0, 6).
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