मराठी

Evaluate the (V) ( 3 + √ 2 ) 5 − ( 3 − √ 2 ) 5 - Mathematics

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प्रश्न

Evaluate the

(v)  \[\left( 3 + \sqrt{2} \right)^5 - \left( 3 - \sqrt{2} \right)^5\]

 

उत्तर

(v) \[(3 + \sqrt{2} )^5 - (3 - \sqrt{2} )^5 \]
\[ = 2\left[^{5}{}{C}_1 \times 3^4 \times (\sqrt{2} )^1 + ^{5}{}{C}_3 \times 3^2 \times (\sqrt{2} )^3 + ^{5}{}{C}_5 \times 3^0 \times (\sqrt{2} )^5 \right]\]

\[= 2[5 \times 81 \times \sqrt{2} + 10 \times 9 \times 2\sqrt{2} + 4\sqrt{2}]\]
\[ = 2\sqrt{2}(405 + 180 + 4) = 1178\sqrt{2}\]

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Introduction of Binomial Theorem
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पाठ 18: Binomial Theorem - Exercise 18.1 [पृष्ठ ११]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 18 Binomial Theorem
Exercise 18.1 | Q 2.05 | पृष्ठ ११

संबंधित प्रश्‍न

Using binomial theorem, write down the expansions  :

(iii)  \[\left( x - \frac{1}{x} \right)^6\]

\[= ^{5}{}{C}_0 (2x )^5 (3y )^0 +^{5}{}{C}_1 (2x )^4 (3y )^1 + ^{5}{}{C}_2 (2x )^3 (3y )^2 + ^{5}{}{C}_3 (2x )^2 (3y )^3 + ^{5}{}{C}_4 (2x )^1 (3y )^4 +^{5}{}{C}_5 (2x )^0 (3y )^5\]

\[= 32 x^5 + 5 \times 16 x^4 \times 3y + 10 \times 8 x^3 \times 9 y^2 + 10 \times 4 x^2 \times 27 y^3 + 5 \times 2x \times 81 y^4 + 243 y^5 \]
\[ = 32 x^5 + 240 x^4 y + 720 x^3 y^2 + 1080 x^2 y^3 + 810x y^4 + 243 y^5 \]

 

 


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