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प्रश्न
evaluate : `int xcosxdx`
उत्तर
`"Let " I=int x cosx dx`
integrating by parts
`I=x int cosx dx-int[d/dx(x)int cosxdx]dx`
`=xsinx-int(sinx)dx+c`
`=xsinx-(-cosx)+c`
`=xsinx+cosx+c`
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