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प्रश्न
Find the distance between P and Q if P lies on the y - axis and has an ordinate 5 while Q lies on the x - axis and has an abscissa 12 .
उत्तर
P lies on y-axis and has ordinate
∴ P (0 , 5)
Q lies on x-axis and has an abscissa
∴ Q (12 , 0)
`therefore "PQ" = sqrt ((12 - 0)^2 + (0 - 5)^2)`
`= sqrt (144 + 25)`
`= sqrt 169`
= 13 units.
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