Advertisements
Advertisements
Question
Find the distance between P and Q if P lies on the y - axis and has an ordinate 5 while Q lies on the x - axis and has an abscissa 12 .
Solution
P lies on y-axis and has ordinate
∴ P (0 , 5)
Q lies on x-axis and has an abscissa
∴ Q (12 , 0)
`therefore "PQ" = sqrt ((12 - 0)^2 + (0 - 5)^2)`
`= sqrt (144 + 25)`
`= sqrt 169`
= 13 units.
APPEARS IN
RELATED QUESTIONS
If the point A(0, 2) is equidistant from the points B(3, p) and C(p, 5), find p. Also, find the length of AB.
Show that four points (0, – 1), (6, 7), (–2, 3) and (8, 3) are the vertices of a rectangle. Also, find its area
If P (2, – 1), Q(3, 4), R(–2, 3) and S(–3, –2) be four points in a plane, show that PQRS is a rhombus but not a square. Find the area of the rhombus
Find the circumcenter of the triangle whose vertices are (-2, -3), (-1, 0), (7, -6).
Find the co-ordinates of points on the x-axis which are at a distance of 17 units from the point (11, -8).
Find the coordinates of the points on the y-axis, which are at a distance of 10 units from the point (-8, 4).
Find distance of point A(6, 8) from origin
Show that P(– 2, 2), Q(2, 2) and R(2, 7) are vertices of a right angled triangle
Point P(0, 2) is the point of intersection of y-axis and perpendicular bisector of line segment joining the points A(–1, 1) and B(3, 3).
Find a point which is equidistant from the points A(–5, 4) and B(–1, 6)? How many such points are there?
