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प्रश्न
Find the equation of a line passing through (-5,-1) and perpendicular to the 3x + y = 9
उत्तर
3x + y = 9
y = -3x + 9
m = -3
Slope of required line = `1/3`
Equation of line is, `("y" - "y"_1)/("x" - "x"_1)` = m
`("y" + 1)/("x" + 5) = 1/3`
⇒ x + 5 = 3y + 3
⇒ x - 3y + 2 = 0
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