Advertisements
Advertisements
प्रश्न
The line through P (5, 3) intersects y-axis at Q.
write the equation of the line
उत्तर
The equation of a line passing through the point
A(x1, y1) with slope ‘m’ is
y – y1 = m (x – x1)
Therefore, the equation of the line passing
through the point P (5, 3) with slope 1 is
y -3 = 1 ×(x – 5)
⇒ y – 3 = x – 5
⇒ x – y = 2
APPEARS IN
संबंधित प्रश्न
A(2, 5), B(–1, 2) and C(5, 8) are the vertices of a triangle ABC, `M' is a point on AB such that AM: MB = 1: 2. Find the coordinates of 'M'. Hence find the equation of the line passing through the points C and M
Solve the following inequation and represent the solution set on the number line 2x – 5 <= 5x + 4 < 11, where x ∈ I
State, true or false :
The point (–3, 0) lies on the line x + 3 = 0
The figure given alongside shows two straight lines AB and CD intersecting each other at point P(3, 4). Find the equations of AB and CD.
Find the equation of the perpendicular dropped from the point (−1, 2) onto the line joining the points (1, 4) and (2, 3).
L is a point on the line segment PQ dividing it in the ratio 1 : 3. If the coordinates of P and Q are (3, 7) and ( 11,-5) respectively, find if L lies on the line 2x + 5y = 20.
Find the inclination of a line whose gradient is 1.4281
A(8,5), B (-2,1) and C(5,4) are the vertices of a triangle. Find the equation of the median of the traingle through C.
Find the equation of a line passing through the intersection of x + 2y + 1= 0 and 2x - 3y = 12 and perpendicular to the line 2x + 3y = 9
A and B are two points on the x-axis and y-axis respectively.
- Write down the coordinates of A and B.
- P is a point on AB such that AP : PB = 1 : 1.
Using section formula find the coordinates of point P. - Find the equation of a line passing through P and perpendicular to AB.
