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प्रश्न
The line through P (5, 3) intersects y-axis at Q.
write the equation of the line
उत्तर
The equation of a line passing through the point
A(x1, y1) with slope ‘m’ is
y – y1 = m (x – x1)
Therefore, the equation of the line passing
through the point P (5, 3) with slope 1 is
y -3 = 1 ×(x – 5)
⇒ y – 3 = x – 5
⇒ x – y = 2
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संबंधित प्रश्न
A line AB meets X – axis at A and Y –axis at B. P (4, -1) divides AB in the ratio 1 : 2.
1) Find the coordinates of A and B.
2) Find the equation of the line through P and perpendicular to AB.
Find, which of the following points lie on the line x – 2y + 5 = 0 :
(0, 5)
Find, which of the following points lie on the line x – 2y + 5 = 0 :
(5, 5)
State, true or false :
The point (8, 7) lies on the line y – 7 = 0
For what value of k will the point (3, −k) lie on the line 9x + 4y = 3?
Find the equation of the perpendicular dropped from the point (−1, 2) onto the line joining the points (1, 4) and (2, 3).
Find the equation of the line with x-intercept 5 and a point on it (–3, 2).
Find the equation of a line passing through (2,5) and making and angle of 30° with the positive direction of the x-axis.
Find the equation of a line passing through (3,7) and making an angle of 60° with the negative direction of the x-axis.
Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0.
