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प्रश्न
Find the equation of the perpendicular dropped from the point (−1, 2) onto the line joining the points (1, 4) and (2, 3).
उत्तर
Let A = (1, 4), B = (2, 3) and C = (−1, 2).
Slope of AB = `(3 - 4)/(2 - 1) = -1`
Slope of equation perpendicular to AB = `(-1)/"slope of AB" = 1`
The equation of the perpendicular drawn through C onto AB is given by:
y − y1 = m(x − x1)
y − 2 = 1(x + 1)
y − 2 = x + 1
y = x + 3
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संबंधित प्रश्न
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