मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Find the area of the region bounded by the curve y = 2x+3, the X axis and the lines x = 0 and x = 2 - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Find the area of the region bounded by the curve y = `sqrt(2x + 3)`, the X axis and the lines x = 0 and x = 2

बेरीज

उत्तर

Let A be the required area.

Given equation of the curve is y = `sqrt(2x + 3)`

∴ A = `int_0^2 y  "d"x`

= `int_0^2 sqrt(2x + 3)  "d"x`

= `int_0^2 (2x + 3)^(1/2)  "d"x`

= `[((2x + 3)^(3/2))/(3/2) xx 1/2]_0^2`

= `1/3[(2x + 3)^(3/2)]_0^2`

= `1/3[(4 + 3)^(5/2) - (0 + 3)^(3/2)]`

= `1/3[(7)^(3/2) - (3)^(3/2)]`

∴ A = `1/3(7sqrt(7) - 3sqrt(3))` sq.units

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1.7: Application of Definite Integration - Q.2

संबंधित प्रश्‍न

Find the area of the region bounded by y2 = 9x, x = 2, x = 4 and the x-axis in the first quadrant.


Area lying in the first quadrant and bounded by the circle x2 + y2 = 4 and the lines x = 0 and x = 2 is ______.


Area of the region bounded by the curve y2 = 4x, y-axis and the line y = 3 is ______.


Find the area between the curves y = x and y = x2


Find the area enclosed between the parabola y2 = 4ax and the line y mx


Find the area of the smaller region bounded by the ellipse `x^2/9 + y^2/4` and the line `x/3 + y/2 = 1`


Draw a rough sketch and find the area bounded by the curve x2 = y and x + y = 2.


Using integration find the area of the triangle formed by negative x-axis and tangent and normal to the circle `"x"^2 + "y"^2 = 9  "at" (-1,2sqrt2)`.


Fill in the blank :

The area of the region bounded by the curve x2 = y, the X-axis and the lines x = 3 and x = 9 is _______.


State whether the following is True or False :

The area bounded by the two cures y = f(x), y = g (x) and X-axis is `|int_"a"^"b" f(x)*dx - int_"b"^"a" "g"(x)*dx|`.


Choose the correct alternative:

Using the definite integration area of the circle x2 + y2 = 16 is ______


Choose the correct alternative:

Area of the region bounded by x = y4, y = 1 and y = 5 and the Y-axis lying in the first quadrant is ______


The area of the region lying in the first quadrant and bounded by the curve y = 4x2, and the lines y = 2 and y = 4 is ______


The area of the region x2 = 4y, y = 1 and y = 2 and the Y axis lying in the first quadrant is ______


The area of the region bounded by the curve y = 4x3 − 6x2 + 4x + 1 and the lines x = 1, x = 5 and X-axis is ____________.


Area bounded by the curve xy = 4, X-axis between x = 1, x = 5 is ______.


The area of the region bounded by the X-axis and the curves defined by y = cot x, `(pi/6 ≤ x ≤ pi/4)` is ______.


The equation of curve through the point (1, 0), if the slope of the tangent to t e curve at any point (x, y) is `(y - 1)/(x^2 + x)`, is


The area (in sq. units) of the region {(x, y) : y2 ≥ 2x and x2 + y2 ≤ 4x, x ≥ 0, y ≥ 0} is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×