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Find the derivative of the inverse function of the following : y = x2 + log x - Mathematics and Statistics

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प्रश्न

Find the derivative of the inverse function of the following : y = x2 + log x

बेरीज

उत्तर

y = x2 + log x
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"(x^2 + logx)`

= `"d"/"dx"(x^2) + "d"/"dx"(logx)`

= `2x + 1/x`

= `(2x^2 + 1)/(x`
The derivative of inverse function of y = f(x) is given by
`"dx"/"dy" = (1)/(("dy"/"dx")`

= `(1)/(((2x^2 + 1)/x)`

= `x/(2x^2 + 1)`.

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Derivatives of Inverse Functions
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Differentiation - Exercise 1.2 [पृष्ठ २९]

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