Advertisements
Advertisements
प्रश्न
Find the equation of the line passing through the points A(–3, 0) and B(0, 4).
उत्तर
Since, the required line passes through the points A(–3, 0) and B(0, 4).
Equation of the line in two point form is
`(y - y_1)/(y_2 - y_1) = (x - x_1)/(x_2 - x_1)`
Here, (x1, y1) = (–3, 0) and (x2, y2) = (0, 4)
∴ the equation of the required line is
`(y - 0)/(4 - 0) = (x - (- 3))/(0 - (- 3))`
∴ `y/4 = (x + 3)/3`
∴ 4x + 12 = 3y
∴ 4x – 3y + 12 = 0
APPEARS IN
संबंधित प्रश्न
Line y = mx + c passes through the points A(2, 1) and B(3, 2). Determine m and c.
The vertices of a triangle are A(3, 4), B(2, 0) and C(1, 6). Find the equations of side BC
The vertices of a triangle are A(3, 4), B(2, 0) and C(1, 6). Find the equation of the median AD.
The vertices of a triangle are A(3, 4), B(2, 0) and C(1, 6). Find the equations of the line passing through the mid points of sides AB and BC.
Find the equations of a line containing the point A(3, 4) and making equal intercepts on the co-ordinate axes.
Write the following equation in ax + by + c = 0 form: `x/2 + y/4` = 1
Write the following equation in ax + by + c = 0 form: `x/3 = y/2`
Reduce the equation 6x + 3y + 8 = 0 into slope-intercept form. Hence, find its slope.
Find the X-intercept of the line x + 2y – 1 = 0
Find the equation of the line: having slope 5 and containing point A(– 1, 2).
Find the equation of the line: having slope 5 and making intercept 5 on the X−axis.
Find the equation of the line: having an inclination 60° and making intercept 4 on the Y-axis.
The vertices of a triangle are A (1, 4), B (2, 3) and C (1, 6). Find equations of the medians
The vertices of a triangle are A (1, 4), B (2, 3) and C (1, 6). Find equations of Perpendicular bisectors of sides
The vertices of a triangle are A (1, 4), B (2, 3) and C (1, 6). Find equations of altitudes of ΔABC
