Advertisements
Advertisements
प्रश्न
Find the product of the following pair of monomial.
− 4p, 7pq
उत्तर
The product will be as follows:
− 4p × 7pq
= − 4 × p × 7 × p × q
= (− 4 × 7) × (p × p × q)
= − 28p2q
APPEARS IN
संबंधित प्रश्न
Find the product of the following pair of monomial.
4p, 0
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
2p, 4q, 8r
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
a, 2b, 3c
Obtain the product of a, 2b, 3c, 6abc.
Express each of the following product as a monomials and verify the result for x = 1, y = 2: \[\left( - \frac{4}{7} a^2 b \right) \times \left( - \frac{2}{3} b^2 c \right) \times \left( - \frac{7}{6} c^2 a \right)\]
Express each of the following product as a monomials and verify the result for x = 1, y = 2:
\[\left( \frac{4}{9}ab c^3 \right) \times \left( - \frac{27}{5} a^3 b^2 \right) \times \left( - 8 b^3 c \right)\]
Multiply: `-2/3"a"^7"b"^2` and `-9/4"a""b"^5`
Solve: ( -3x2 ) × ( -4xy)
Solve: (-12x) × 3y2
Three consecutive integers, when taken in increasing order and multiplied by 2, 3 and 4 respectively, total up to 74. Find the three numbers.