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प्रश्न
Find the value of discriminant of the following equation.
2y2 − y + 2 = 0
उत्तर
2y2 − y + 2 = 0
For the quadratic equation, ax2 + bx + c = 0
D = b2 − 4ac
Here,
a = 2, b = −1, c = 2
D = (−1)2 − 4 × 2 × 2
= 1 − 16
= −15
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Activity:
Let α = 2 and β = 5 are the roots of the quadratic equation.
Then quadratic equation is:
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∴ `x^2 - (2 + square)x + square xx 5 = 0`
∴ `x^2 - square x + square = 0`
