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प्रश्न
Find the value of the following:
sin 76° cos 16° – cos 76° sin 16°
उत्तर
Given that, sin 76° cos 16° – cos 76° sin 16° (∴ This is of the form sin(A – B))
= sin(76° – 16°)
= sin 60°
`= sqrt3/2`
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