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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Give a scientific reason. Simple microscope is used for watch repairs. - Science and Technology 1

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प्रश्न

Give a scientific reason.

Simple microscope is used for watch repairs.

कारण सांगा

उत्तर १

  1. When an object is put inside the focal length of a magnifying glass or simple microscope (convex lens), the larger and erect image appears on the same side of the lens as the object.
  2. By altering the distance between the object and the lens, the image can be obtained at the shortest distance of distinct vision. Thus, a watch repairer may see the minute parts of a watch more clearly with the use of a magnifying glass (a rudimentary microscope) than with the naked eye, and without putting any strain on the eye. As a result, watch repairers utilise a magnifying glass (a basic microscope) to repair the timepieces.
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उत्तर २

  1. In a simple microscope, a convex lens with a small focal length is used.
  2. It produces a virtual, erect, and bigger image of an object.
  3. We can get a 20 times larger image of an object using a simple microscope.

Hence, watch repairers use a simple microscope while repairing watches.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Lenses - Write scientific reasons

संबंधित प्रश्‍न

A converging lens has focal length of 12 cm. Calculate at what distance the object should be placed from the lens so that it forms an image at 48 cm on the other side of the lens.


An object of height 4 cm is placed at a distance of 20 cm from a concave lens of focal length 10 cm. Use lens formula to determine the position of the image formed.


A student wants to project the image of a candle flame on a screen 60 cm in front of a mirror by keeping the flame at a distance of 15 cm from its pole.

(a) Write the type of mirror he should use.

(b) Find the linear magnification of the image produced.

(c) What is the distance between the object and its image?

(d) Draw a ray diagram to show the image formation in this case.


At what distance from a concave lens of focal length 20 cm, should a 6 cm tall object be placed so that it forms an image at 15 cm from the lens ? Also determine the size of the image formed.


A student has obtained an image of a distant object on a screen to determine the focal length F1 of the given lens. His teacher, after checking the image, gave him another lens of  focal length F2 and asked him to focus the same object on the same screen. The student found that to obtain a sharp image, he has to move the lens away from the screen. From this finding, we may conclude that both the lenses given to the student were :

(A) Concave and F1 < F2

(B) Convex and F1 < F2

(C) Convex and F1 > F2

(D) Concave and F1 > F2


A student was asked by his teacher to find the image distance for various object distance in case of a given convex lens. He performed the experiment with all precautions and noted down his observations in the following table:

S. No.

Object distance

(cm)

Image distance

(cm)

1 60 15
2 48 16
3 36 21
4 24 24
5 18 36
6 16 48

After checking the observations table the teacher pointed out that there is a mistake in recording the image distance in one of the observations. Find the serial number of the observations having faulty image distance.

(A) 2

(B) 3

(C) 5

(D) 6


An object is held 20 cm away from a converging lens of focal length 10 cm. Find the position of the image formed.


The image seen in a plane mirror cannot be formed on a screen. What name is given to this type of image?


In order to obtain a magnification of −2 (minus 2) with a concave mirror, the object should be placed:

(a) between pole and focus
(b) between focus and centre of curvature
(c) at the centre of curvature
(d) beyond the centre of curvature


In order to obtain a magnification of, −1.5 with a concave mirror of focal length 16 cm, the object will have to be placed at a distance 

(a) between 6 cm and 16 cm
(b) between 32 cm and 16 cm
(c) between 48 cm and 32 cm
(d) beyond 64 cm


Explain what is meant by a virtual, magnified image. 


 Draw a ray diagram to show the formation of a virtual magnified image of an object by a convex lens. In your diagram, the position of object and image with respect to the principal focus should be shown clearly. 


The lens A produces a magnification of, − 0.6 whereas lens B produces a magnification of + 0.6.  

 What is the nature of lens A?


The lens A produces a magnification of, − 0.6 whereas lens B produces a magnification of + 0.6. 

What is the nature of lens B


Draw a ray diagram to show how a converging lens is used as a magnifying glass to observe a small object. Mark on your diagram the foci of the lens and the position of the eye.


A student wants to project the image of a candle flame on a screen 80 cm in front of a mirror by keeping the candle flame at a distance of 20 cm from its pole.

  1. Which type of mirror should the student use?
  2. Find the magnification of the image produced.
  3. Find the distance between the object and its image.
  4. Draw a ray diagram to show the image formation in this case and mark the distance between the object and its image.

To determine focal length of a concave mirror a student obtains the image of a well lit distant object on a screen. To determine the focal length of the given concave mirror he needs to measure the distance between:

(A) mirror and the object

(B) mirror and the screen

(C) screen and the object

(D) screen and the object and also mirror and the screen


The image of a candle flame placed at a distance 36 cm from a spherical lens is formed on a screen placed at a distance of 72 cm from the lens. Identify the type of lens and calculate its focal length. If the height of the flame is 2.5 cm, find the height of its image.


At which position will you keep an object in front of a convex lens so as to get a real image of the same size as the object? Draw a figure.


Solve the following example.
5 cm high object is placed at a distance of 25 cm from a converging lens of focal length of 10 cm. Determine the position, size and type of the image.


Solve the following example.

An object kept 60 cm from a lens gives a virtual image 20 cm in front of the lens. What is the focal length of the lens? Is it a converging lens or diverging lens?


A lens forms the image of an object placed at a distance 15 cm from it, at a distance 60 cm in front of it. Find the magnification.


Find the position and magnification of the image of an object placed at distance of 8.0 cm in front of a convex lens of focal length 10.0 cm. Is the image erect or inverted?


The image of a candle flame formed by a lens is obtained on a screen placed on the other side of the lens. If the image is three times the size of the flame and the distance between lens and image is 80 cm, at what distance should the candle be placed from the lens? What is the nature of the image at a distance of 80 cm and the lens?


The focal length of a concave lens is 20 cm. At what distance from the lens should a 5 cm tall object be placed so that its image is formed at a distance of 15 cm from the lens? Also calculate the size of the image formed.


The magnification by a lens is -3. Name the lens and state how are u and v related?


What information about the nature of image is erect or inverted, do you get from the sign of magnification + or -?


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