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प्रश्न
How much charge in terms of Faraday is required for the reduction of 1 mol of Cu2+ to Cu?
उत्तर
The reduction of one mol of Cu2+ to Cu can be represented as:
\[\ce{Cu^{2+} + 2e^- -> Cu}\]
Since, in this reaction, there are two moles of electrons involved, the amount of charge required is 2F.
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