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प्रश्न
If 1 is a zero of the polynomial p(x) = ax2 − 3(a − 1) x − 1, then find the value of a.
उत्तर
Given,
p(x) = ax2 − 3(a − 1) x − 1
Zero is 1
Now,
p(1) = a(1)2 – 3(a – 1) ×1 – 1 = 0
p(1) = a – 3a + 3 – 1 = 0
p(1) = – 2a + 2 = 0
= – 2a = – 2
= a = `(-2)/-2 = 1`
So the value of a = 1
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