Advertisements
Advertisements
प्रश्न
If -4 is a zero of the polynomial `x^2 – x – (2k + 2) is –4`, then find the value of k.
उत्तर
Given: x = –4 is one zero of the polynomial `x^2 – x – (2k + 2)`
Therefore, it will satisfy the above polynomial.
Now, we have
`(–4)^2 – (–4) – (2k + 2) = 0`
`⇒ 16 + 4 – 2k – 2 = 0`
`⇒ 2k = – 18`
`⇒ k = 9`
APPEARS IN
संबंधित प्रश्न
The graphs of y = p(x) are given in following figure, for some polynomials p(x). Find the number of zeroes of p(x).
If one zero of the polynomial `x^2-4x+1 is (2+sqrt3)` , write the other zero.
If one zero of the quadratic polynomial `kx^2 + 3x + k is 2`, then find the value of k.
If one zero of the quadratic polynomial x2 + 3x + k is 2, then the value of k is ______.
10. The zeroes of the quadratic polynomial x² + kx + k, k? 0.
If the zeroes of the quadratic polynomial ax² + bx + c, c # 0 are equal, then ______.
If x3 + 1 is divided by x2 + 5, then the possible degree of quotient is ______.
If p(x) is a polynomial of at least degree one and p(k) = 0, then k is known as ______.
The zeroes of the quadratic polynomial x2 + kx + k, k ≠ 0 ______.
The zeroes of the polynomial 3x2 + 11x – 4 are ______.
