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If the Earth'S Magnetic Field Has a Magnitude 3.4 × 10−5 T at the Magnetic Equator of the Earth, What Would Be Its Value at the Earth'S Geomagnetic Poles? - Physics

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प्रश्न

If the earth's magnetic field has a magnitude 3.4 × 10−5 T at the magnetic equator of the earth, what would be its value at the earth's geomagnetic poles?

बेरीज

उत्तर

Given :

Magnetic field at the magnetic equator, B = 3.4 × 10−5 T
Let M be the magnetic moment of Earth's magnetic dipole and R be the distance of the observation point from the centre of Earth's magnetic dipole. 
As the point on the magnetic equator is on the equatorial position of Earth's magnet, the magnetic field at the equatorial point (B) is given by

`B = u_0/(4pi) M/R^3`

⇒ `u_0/(4pi) xx M/R^3 = 3.4 xx 10^-5`

⇒ `M = (3.4 xx 10^-5 xx R^3 xx 4pi)/(4pi xx 10^-7)`

⇒  `M = 3.4 xx 10^2 R^3`

As the magnetic field on Earth's geomagnetic poles lies on the axial point of the magnetic dipole, the magnetic field at the axial point `(B_1)` is given by

`vec(B_1) = u_0/(4pi) xx (2M)/R^3`

⇒ `B_1 = (10^-7 xx 2 xx 3.4 xx 10^2 xx R^3)/(R^3)`

⇒ `B_1 = 6.8 xx 10^-5  "T"`

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पाठ 14: Permanent Magnets - Exercises [पृष्ठ २७७]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 14 Permanent Magnets
Exercises | Q 12 | पृष्ठ २७७

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