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प्रश्न
If θ is an acute angle and sin θ = cos θ, find the value of tan2 θ + cot2 θ – 2.
उत्तर
Given, sin θ = cos θ
`sinθ/cosθ` = 1
tan θ = 45°
`\implies` θ = 45°
So tan2 θ + cot2 θ – 2 = tan2 45° + cot2 45° – 2
= 1 + 1 – 2
= 0
∴ tan2 θ + cot2 θ – 2 = 0
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