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Given sec θ = 1312, calculate all other trigonometric ratios. - Mathematics

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प्रश्न

Given sec θ = `13/12`, calculate all other trigonometric ratios.

बेरीज

उत्तर

Let ΔABC be a right-angled triangle, right angled at point B.

It is given that:

sec θ = `"hypotenuse"/"side adjacent to ∠θ" = "AC"/"AB" = 13/12`

Let AC = 13k and AB = 12k, where k is a positive integer.

Applying pythagoras theorem in Δ ABC, we obtain:

AC2 = AB2 + BC2

BC2 = AC2 - AB2

BC2 = (13k)2 - (12k)2

BC2 = 169 k2 - 144 k2

BC2 = 25k2

BC = 5k

sin θ = `("side opposite to ∠θ")/("hypotenuse") = ("BC")/("AC") = 5/13`

cos θ = `("side adjacent to ∠θ")/("hypotenuse") = ("AB")/("AC") = 12/13`

tan θ = `("side opposite to ∠θ")/("side adjacent to ∠θ") = "(BC)"/"(AB)" = 5/12`

cot θ = `("side adjacent to ∠θ")/("side opposite to ∠θ") = ("AB")/("BC") = 12/5`

cosec θ = `("hypotenuse")/("side opposite to ∠θ") = ("AC")/("BC") = 13/5`

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पाठ 8: Introduction to Trigonometry - Exercise 8.1 [पृष्ठ १८१]

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एनसीईआरटी Mathematics [English] Class 10
पाठ 8 Introduction to Trigonometry
Exercise 8.1 | Q 5 | पृष्ठ १८१

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