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If n is an odd positive integer, prove that the coefficients of the middle terms in the expansion of (x + y)n are equal - Mathematics

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प्रश्न

If n is an odd positive integer, prove that the coefficients of the middle terms in the expansion of (x + y)n are equal

बेरीज

उत्तर

Given n is odd.

So let n = 2n + 1

Where n is an integer.

The expansion (x + y)n has n + 1 terms.

= 2n + 1 + 1

= 2(n + 1) terms which is an even number.

So the middle term are `("t"^2("n"+ 1))/2` = tn+1

`"t"_(2("n" + 1))` = tn+1 and `"t"_("n" +  + 1)` = tn+2

(i.e.) The middle terms are tn+1 and tn+2

tn+1 = `""^(2"n" + 1)"C"_"n"` and tn+2

= `"t"_(n" + 1 + 1)`

= 2n + 1Cn+1

Now n + n + 1 = 2n + 1

⇒ `""^(2"n" + 1)"C"_"n" = ""^(2"n" + 1)"C"_("n" + 1)`

⇒ The coefficient of the middle terms in (x + y)n are equal.

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Binomial Theorem
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Binomial Theorem, Sequences and Series - Exercise 5.1 [पृष्ठ २१०]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 5 Binomial Theorem, Sequences and Series
Exercise 5.1 | Q 10 | पृष्ठ २१०
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