Advertisements
Advertisements
प्रश्न
If the surface area of a sphere is 2826 cm2 then find its volume. ( π= 3.14)
उत्तर
Let the radius of the sphere be r cm.
Surface area of the sphere = 2826 cm2
∴ 4πr2 = 2826 cm2
⇒ r2 = ` [2826]/[4 xx 3.14]`
⇒ r2 = 225
⇒ r = `sqrt 225`
⇒ r = 15 cm
∴ Volume of the sphere = `4/3π"r"^3`
= `4/3 xx 3.14 xx (15)^3`
= 14130 cm3
Thus, the volume of the sphere is 14130 cm3.
APPEARS IN
संबंधित प्रश्न
A model of a ship is made to a scale 1: 300
1) The length of the model of the ship is 2 m. Calculate the lengths of the ship.
2) The area of the deck ship is 180,000 m2. Calculate the area of the deck of the model.
3) The volume of the model in 6.5 m3. Calculate the volume of the ship.
A solid cone of radius 5 cm and height 8 cm is melted and made into small spheres of radius 0.5 cm. Find the number of spheres formed.
The diameter of the moon is approximately one fourth of the diameter of the earth. Find the
ratio of their surface areas.
A largest sphere is to be carved out of a right circular cylinder of radius 7 cm and height 14 cm. Find the volume of the sphere.
If a solid sphere of radius r is melted and cast into the shape of a solid cone of height r, then the radius of the base of the cone is
Find the volume of a sphere, if its surface area is 154 sq.cm.
The surface area of a solid metallic sphere is 616 cm2. It is melted and recast into smaller spheres of diameter 3.5 cm. How many such spheres can be obtained?
A spherical ball of radius 3 cm is melted and recast into three spherical balls. The radii of two of the balls are 1.5 cm and 2 cm. Find the diameter of the third ball.
A solid sphere is cut into two identical hemispheres.
Statement 1: The total volume of two hemispheres is equal to the volume of the original sphere.
Statement 2: The total surface area of two hemispheres together is equal to the surface area of the original sphere.
Which of the following is valid?
A manufacturing company prepares spherical ball bearings, each of radius 7 mm and mass 4 gm. These ball bearings are packed into boxes. Each box can have maximum of 2156 cm3 of ball bearings. Find the:
- maximum number of ball bearings that each box can have.
- mass of each box of ball bearings in kg.
(use π = `22/7`)
