Advertisements
Advertisements
प्रश्न
If V = pr2h and S = 2pr2 + 2prh, then express V in terms of S, p and r.
उत्तर
V = πr2h and S = 2πr2 + 2πrh
S = 2πr2 + 2πrh
⇒ 2rh = S - 2πr2
⇒ h = `("S" - 2pi"r"^2)/(2pi"r")`
Substitute h in V = πr2h
⇒ V = `pi"r"^2(("S" - 2pi"r"^2)/(2pi"r"))`
⇒ V = `"r"(("S" - 2pi"r"^2)/(2))`
⇒ V = `"Sr"/(2) - pi"r"^3`.
APPEARS IN
संबंधित प्रश्न
Make L the subject of formula T = `2pisqrt("L"/"G")`
Make r2 the subject of formula `(1)/"R" = (1)/"r"_1 + (1)/"r"_2`
Make a the subject of formula x = `sqrt(("a" + "b")/("a" - "b")`
If b = `(2"a")/("a" - 2)`, and c = `(4"b" - 3)/(3"b" + 4)`, then express c in terms of a.
Make a the subject of the formula S = `"n"/(2){2"a" + ("n" - 1)"d"}`. Find a when S = 50, n = 10 and d = 2.
Make y the subject of the formula `x/"a" + y/"b" `= 1. Find y, when a = 2, b = 8 and x = 5.
Make I the subject of the following M = `"L" /"F"(1/2"N" - "C") xx "I"`. Find I, If M = 44, L = 20, F = 15, N = 50 and C = 13.
"The volume of a cylinder V is equal to the product of π and square of radius r and the height h". Express this statement as a formula. Make r the subject formula. Find r, when V = 44cm3, π = `(22)/(7)`, h = 14cm.
"The volume of a cone V is equal to the product of one third of π and square of radius r of the base and the height h". Express this statement as a formula. Make r the subject formula. Find r, when V = 1232cm3, π = `(22)/(7)`, h = 24cm.
The pressure P and volume V of a gas are connected by the formula PV = C; where C is a constant. If P = 4 when V = `2(1)/(2)`; find the value of P when V = 4?