Advertisements
Advertisements
प्रश्न
If V = pr2h and S = 2pr2 + 2prh, then express V in terms of S, p and r.
उत्तर
V = πr2h and S = 2πr2 + 2πrh
S = 2πr2 + 2πrh
⇒ 2rh = S - 2πr2
⇒ h = `("S" - 2pi"r"^2)/(2pi"r")`
Substitute h in V = πr2h
⇒ V = `pi"r"^2(("S" - 2pi"r"^2)/(2pi"r"))`
⇒ V = `"r"(("S" - 2pi"r"^2)/(2))`
⇒ V = `"Sr"/(2) - pi"r"^3`.
APPEARS IN
संबंधित प्रश्न
A man bought 25a articles at 30p paisa each and sold them at 20q paisa each. Find his profit in rupees.
Make y the subject of formula W = `"pq" + (1)/(2)"wy"^2`
Make V the subject of formula K = `(1)/(2)"MV"^2`
Make d the subject of formula S = `"n"/(2){2"a" + ("n" - 1)"d"}`
Make x the subject of the formula a = `1 - (2"b")/("cx" - "b")`. Find x, when a = 5, b = 12 and
Make y the subject of the formula `x/"a" + y/"b" `= 1. Find y, when a = 2, b = 8 and x = 5.
Make I the subject of the following M = `"L" /"F"(1/2"N" - "C") xx "I"`. Find I, If M = 44, L = 20, F = 15, N = 50 and C = 13.
Make g the subject of the formula v2 = u2 - 2gh. Find g, when v = 9.8, u = 41.5 and h = 25.4.
Make z the subject of the formula y = `(2z + 1)/(2z - 1)`. If x = `(y + 1)/(y - 1)`, express z in terms of x, and find its value when x = 34.
"Area A oof a circular ring formed by 2 concentric circles is equal to the product of pie and the difference of the square of the bigger radius R and the square of the bigger radius R and the square of the smaller radius r. Express the above statement as a formula. Make r the subject of the formula and find r, when A = 88 sq cm and R = 8cm.