Advertisements
Advertisements
प्रश्न
If X = a2 – 1 and Y = 1 – b2, then find X + Y and factorize the same
उत्तर
Given X = a2 – 1
Y = 1 – b2
X + Y = (a2 – 1) + (1 – b2)
= a2 – 1 + 1 – b2
We know the identity that a2 – b2 = (a + b)(a – b)
∴ X + Y = (a + b)(a – b)
APPEARS IN
संबंधित प्रश्न
Choose the right answers from the option:
The difference of the squares, (612 – 512 ) is equal to ______.
Using suitable identities, evaluate the following.
9.8 × 10.2
Using suitable identities, evaluate the following.
(9.7)2 – (0.3)2
Using suitable identities, evaluate the following.
(339)2 – (161)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x2 – 9
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
28ay2 – 175ax2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
49x2 – 36y2
The sum of first n natural numbers is given by the expression `n^2/2 + n/2`. Factorise this expression.
The base of a parallelogram is (2x + 3 units) and the corresponding height is (2x – 3 units). Find the area of the parallelogram in terms of x. What will be the area of parallelogram of x = 30 units?
Verify the following:
`((3p)/7 + 7/(6p))^2 - (3/7p + 7/(6p))^2 = 2`