Advertisements
Advertisements
प्रश्न
If x3 + 6x2 + kx + 6 is exactly divisible by (x + 2), then k = ?
पर्याय
−6
−7
−8
11
उत्तर
11
Explanation;
Hint:
p(x) = x3 + 6x2 + kx + 6
Given p(−2) = 0
(−2)3 + 6(−2)2 + k(−2) + 6 = 0
−8 + 24 – 2k + 6 = 0
22 – 2k = 0
k = `22/2`
= 11
APPEARS IN
संबंधित प्रश्न
Find the remainder when x4 + 1 is divided by x + 1.
Find ‘a‘ if the two polynomials ax3 + 3x2 – 9 and 2x3 + 4x + a, leave the same remainder when divided by x + 3.
Using the Remainder Theorem, factorise the following completely:
x3 + x2 – 4x – 4
Find the value of ‘m’, if mx3 + 2x2 – 3 and x2 – mx + 4 leave the same remainder when each is divided by x – 2.
Find the values of a and b when the polynomial f(x)= ax3 + 3x2 +bx -3 is exactly divisible by (2x+3) and leaves a remainder -3 when divided by (x+2).
When x3 + 3x2 – kx + 4 is divided by (x – 2), the remainder is k. Find the value of k.
Find the remainder (without division) on dividing f(x) by (2x + 1) where f(x) = 4x2 + 5x + 3
When 2x3 – 9x2 + 10x – p is divided by (x + 1), the remainder is – 24.Find the value of p.
By remainder theorem, find the remainder when, p(x) is divided by g(x) where, p(x) = x3 – 2x2 – 4x – 1; g(x) = x + 1
Determine which of the following polynomials has x – 2 a factor:
4x2 + x – 2
