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प्रश्न
In ∆LMN, MN is extended to O. If ∠MLN = 100 – x, ∠LMN = 2x and ∠LNO = 6x – 5, find the value of x
उत्तर
Exterior angle is equal to the sum of the opposite interior angles
∠LNO = ∠MLN + ∠LMN
6x – 5 = 100° – x + 2x
6x – 5 + x – 2x = 100°
6x + x – 2x = 100° + 5°
5x = 105°
x = `(105^circ)/5` = 21°
x = 21°
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