मराठी
तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान इयत्ता ११

In the equilibrium, 2A(g)↽−−⇀2B(g)+CX2(g) the equilibrium concentrations of A, B and C2 at 400 K are - Chemistry

Advertisements
Advertisements

प्रश्न

In the equilibrium,

\[\ce{2A(g) <=> 2B(g) + C2(g)}\]

the equilibrium concentrations of A, B and C2 at 400 K are 1 × 10–4 M, 2.0 × 10–3 M, 1.5 × 10–4 M respectively. The value of KC for the equilibrium at 400 K is

पर्याय

  • 0.06

  • 0.09

  • 0.62

  • 3 × 10-2

MCQ

उत्तर

0.06

shaalaa.com
Equilibrium Constants
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Physical and Chemical Equilibrium - Evaluation [पृष्ठ २३]

APPEARS IN

सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 11 TN Board
पाठ 8 Physical and Chemical Equilibrium
Evaluation | Q I. 8. | पृष्ठ २३

संबंधित प्रश्‍न

An equilibrium constant of 3.2 × 10-6 for a reaction means, the equilibrium is


In which of the following equilibrium, Kp and Kc are not equal?


The equilibrium constants of the following reactions are:

\[\ce{N2 + 3H2 <=> 2NH3}\]; K1

\[\ce{N2 + O2 <=> 2NO}\]; K2

\[\ce{H2 + 1/2O2 <=> H2O}\]; K3

The equilibrium constant (K) for the reaction;

\[\ce{2NH3 + 5/2 O2 <=> 2NO + 3H2O}\], will be


For a given reaction at a particular temperature, the equilibrium constant has a constant value. Is the value of Q also constant? Explain.


When the numerical value of the reaction quotient (Q) is greater than the equilibrium constant, in which direction does the reaction proceed to reach equilibrium?


For the reaction, \[\ce{A2(g) + B2(g) <=> 2AB(g); \Delta H}\] is -ve.

the following molecular scenes represent differenr reaction mixture. (A-green, B-blue)

Closed 
System At equilibrium (x) (y)
  1. Calculate the equilibrium constant Kp and (Kc).
  2. For the reaction mixture represented by scene (x), (y) the reaction proceed in which directions?
  3. What is the effect of an increase in pressure for the mixture at equilibrium?

Write the balanced chemical equation for an equilibrium reaction for which the equilibrium constant is given by expression.

`"K"_"C" = (["NH"_3]^4["O"_2]^5)/(["NO"]^4["H"_2"O"]^6)`


At particular temperature Kc = 4 × 10-2 for the reaction, \[\ce{H2S (g) <=> H2(g) +1/2 S2(g)}\]. Calculate the Kc for the following reaction.

\[\ce{3H2S (g) <=> 3H2 (g) + 3/2 S2 (g)}\]


The equilibrium for the dissociation of XY2 is given as,

\[\ce{2 XY2 (g) <=> 2 XY (g) + Y2 (g)}\]

if the degree of dissociation x is so small compared to one. Show that 2 Kp = PX3 where P is the total pressure and Kp is the dissociation equilibrium constant of XY2.


The equilibrium constant Kp for the reaction \[\ce{N2 (g) + 3H2 (g) <=> 2NH3 (g)}\] is 8.19 × 102 at 298 K and 4.6 × 10-1 at 498 K. Calculate ∆H° for the reaction.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×