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प्रश्न
An equilibrium constant of 3.2 × 10-6 for a reaction means, the equilibrium is
पर्याय
largely towards forward direction
largely towards reverse direction
never established
none of these
उत्तर
largely towards reverse direction
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संबंधित प्रश्न
Which one of the following is incorrect statement ?
In which of the following equilibrium, Kp and Kc are not equal?
\[\ce{[CO(H2O)6]^2+ (aq) (pink) + 4Cl- (aq) <=> [CoCl4]^2- (aq) (blue) + 6 H2O (l)}\]
In the above reaction at equilibrium, the reaction mixture is blue in colour at room temperature. On cooling this mixture, it becomes pink in color. On the basis of this information, which one of the following is true?
What is the relation between Kp and Kc? Given one example for which Kp is equal to Kc.
When the numerical value of the reaction quotient (Q) is greater than the equilibrium constant, in which direction does the reaction proceed to reach equilibrium?
For the reaction, \[\ce{A2(g) + B2(g) <=> 2AB(g); \Delta H}\] is -ve.
the following molecular scenes represent differenr reaction mixture. (A-green, B-blue)
Closed ← |
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System | At equilibrium | (x) | (y) |
- Calculate the equilibrium constant Kp and (Kc).
- For the reaction mixture represented by scene (x), (y) the reaction proceed in which directions?
- What is the effect of an increase in pressure for the mixture at equilibrium?
What is the effect of added Inert gas on the reaction at equilibrium?
At particular temperature Kc = 4 × 10-2 for the reaction, \[\ce{H2S (g) <=> H2(g) +1/2 S2(g)}\]. Calculate the Kc for the following reaction.
\[\ce{3H2S (g) <=> 3H2 (g) + 3/2 S2 (g)}\]
The equilibrium for the dissociation of XY2 is given as,
\[\ce{2 XY2 (g) <=> 2 XY (g) + Y2 (g)}\]
if the degree of dissociation x is so small compared to one. Show that 2 Kp = PX3 where P is the total pressure and Kp is the dissociation equilibrium constant of XY2.
The equilibrium constant Kp for the reaction \[\ce{N2 (g) + 3H2 (g) <=> 2NH3 (g)}\] is 8.19 × 102 at 298 K and 4.6 × 10-1 at 498 K. Calculate ∆H° for the reaction.