Advertisements
Advertisements
प्रश्न
In the figure given alongside, AB and CD are straight lines through the centre O of a circle. If ∠AOC = 80° and ∠CDE = 40°, find the number of degrees in ∠ABC.
उत्तर
In ΔBOC,
∠AOC = ∠OCB + ∠OBC
(Exterior angle of a Δ is equal to the sum of pair of interior opposite angles)
`=>` ∠OBC = 80° – 50° = 30° ...[∠AOC = 80°, given]
Hence, ∠ABC = 30°
APPEARS IN
संबंधित प्रश्न
AB is a diameter of the circle APBR as shown in the figure. APQ and RBQ are straight lines. Find : ∠PRB
If two sides of a cyclic quadrilateral are parallel; prove that:
- its other two sides are equal.
- its diagonals are equal.
In the given circle with diameter AB, find the value of x.
In the given figure, AB = AD = DC = PB and ∠DBC = x°. Determine, in terms of x :
- ∠ABD,
- ∠APB.
Hence or otherwise, prove that AP is parallel to DB.
In the figure, given below, CP bisects angle ACB. Show that DP bisects angle ADB.
In the figure, given below, AD = BC, ∠BAC = 30° and ∠CBD = 70°.
Find:
- ∠BCD
- ∠BCA
- ∠ABC
- ∠ADB
A triangle ABC is inscribed in a circle. The bisectors of angles BAC, ABC and ACB meet the circumcircle of the triangle at points P, Q and R respectively. Prove that :
∠ACB = 2∠APR,
A triangle ABC is inscribed in a circle. The bisectors of angles BAC, ABC and ACB meet the circumcircle of the triangle at points P, Q and R respectively. Prove that :
`∠QPR = 90^circ - 1/2 ∠BAC`
In the given figure, ∠BAD = 65°, ∠ABD = 70° and ∠BDC = 45°. Find: ∠ ACB.
Hence, show that AC is a diameter.
If I is the incentre of triangle ABC and AI when produced meets the cicrumcircle of triangle ABC in points D. f ∠BAC = 66° and ∠ABC = 80°. Calculate : ∠BIC.