Advertisements
Advertisements
प्रश्न
In the figure, line l is parallel to X-axis. Which of the following statement is true?
पर्याय
The slope is zero.
The slope cannot be determined.
The slope is positive.
The slope is negative.
उत्तर
The slope is zero.
Explanation:
The slope of a line parallel to the X-axis is zero.
APPEARS IN
संबंधित प्रश्न
The slope of a line joining P(6, k) and Q(1 – 3k, 3) is `1/2`. Find:
- k.
- mid-point of PQ, using the value of ‘k’ found in (i).
Show that the points P(a, b + c), Q(b, c + a) and R(c, a + b) are collinear.
Lines mx + 3y + 7 = 0 and 5x – ny – 3 = 0 are perpendicular to each other. Find the relation connecting m and n.
Find the value of p if the lines, whose equations are 2x – y + 5 = 0 and px + 3y = 4 are perpendicular to each other.
If the lines y = 3x + 7 and 2y + px = 3 are perpendicular to each other, find the value of p.
The line through A(−2, 3) and B(4, b) is perpendicular to the line 2x – 4y = 5. Find the value of b.
Find the slope of the lines passing through the given point.
A(2, 3), B(4, 7)
Determine whether the following point is collinear.
L(2, 5), M(3, 3), N(5, 1)
Find k, if PQ || RS and P(2, 4), Q (3, 6), R(3, 1), S(5, k).
Determine whether the given point is collinear.
L(1,2), M(5,3) , N(8,6)
Find k if the line passing through points P(–12, –3) and Q(4, k) has slope \[\frac{1}{2}\].
Show that the line joining the points A(4, 8) and B(5, 5) is parallel to the line joining the points C(2, 4) and D(1, 7).
Show that points P(1, –2), Q(5, 2), R(3, –1), S(–1, –5) are the vertices of a parallelogram.
Find the slope of a line, correct of two decimals, whose inclination is 30°
Find the slope of a line passing through the given pair of points (9,-2) and (-5,5)
Find the slope of a line parallel to the given line 5x-y = 10
Find the slope and the y-intercept of the following line 2x + 3y = 12
Verify whether the following points are collinear or not:
A(1, –3), B(2, –5), C(–4, 7).
Show that the points A(- 2, 5), B(2, – 3) and C(0, 1) are collinear.
Determine whether the following points are collinear. A(–1, –1), B(0, 1), C(1, 3)
Given: Points A(–1, –1), B(0, 1) and C(1, 3)
Slope of line AB = `(square - square)/(square - square) = square/square` = 2
Slope of line BC = `(square - square)/(square - square) = square/square` = 2
Slope of line AB = Slope of line BC and B is the common point.
∴ Points A, B and C are collinear.