Advertisements
Advertisements
प्रश्न
In the given figure, AB and CD are diameters of a circle with centre O perpendicular to each other. If OA = 7 cm, find the area of shaded region.
उत्तर
Radius of circle (r) = OA = 7 cm.
Area of the semicircle = `1/2xxpi"r"^2`
= `1/2xx22/7xx7xx7`
= 11 × 7
= 77 cm2
Area of ΔABC = `1/2` × base × height
= `1/2xx14xx7`
= 49 cm2
.·. Area of the shaded portion = Area of semicircle - Area of the ΔABC
= 77 - 49
= 28 cm2
APPEARS IN
संबंधित प्रश्न
In fig. 3, a square OABC is inscribed in a quadrant OPBQ of a circle. If OA = 20 cm, find the area of the shaded region. (Use π = 3.14)
Find the area of the shaded region in the given figure, if ABCD is a square of side 14 cm and APD and BPC are semicircles. [Use Π = 22/7]
In the given figure, ABCD is a square of side 14 cm. With centres A, B, C and D, four circles are drawn such that each circle touches externally two of the remaining three circles. Find the area of the shaded region. [Use Π = 22/7]
In the given figure, AB and CD are two diameters of a circle (with centre O) perpendicular to each other and OD is the diameter of the smaller circle. If OA = 7 cm, find the area of the shaded region. [Use Π = 22/7]
Find the areas of the triangle whose sides are 42 cm, 34 cm and 20 cm. Also, find the height corresponding to the longest side.
The perimeter of a triangular field is 240m, and its sides are in the ratio 25:17:12. Find the area of the field. Also, find the cost of ploughing the field at ₹ 40 per `m^2`
If the area of an equilateral triangle is `81sqrt3 cm^2` find its height.
In Figure 5, ABCD is a quadrant of a circle of radius 28 cm and a semi circle BEC is drawn with BC as diameter. Find the area of the shaded region ?\[[Use\pi = \frac{22}{7}]\]
In Fig. 7, PQ and AB are respectively the arcs of two concentric circles of radii 7 cm and
3.5 cm and centre O. If ∠POQ = 30°, then find the area of the shaded region. [User`22/7`]
Find the area of the shaded region in figure.
