Advertisements
Advertisements
प्रश्न
In triangle ABC, line I, is a perpendicular bisector of BC.
If BC = 12 cm, SM = 8 cm, find CS
उत्तर
Given l1, is the perpendicular bisector of BC.
∴ ∠SMC = 90°and BM = MC
BC = 12 cm
⇒ BM + MC = 12 cm
MC + MC = 12 cm
2MC = 12
MC = `12/2`
MC = 6 cm
Given SM = 8 cm
By Pythagoras theorem SC2 = SM2 + MC2
SC2 = 82 + 62
SC2 = 64 + 36
CS2 = 100
CS2 = 102
CS = 10 cm
APPEARS IN
संबंधित प्रश्न
Sides of triangle are given below. Determine it is a right triangle or not? In case of a right triangle, write the length of its hypotenuse. 13 cm, 12 cm, 5 cm
In an isosceles triangle, length of the congruent sides is 13 cm and its base is 10 cm. Find the distance between the vertex opposite the base and the centroid.
In ΔMNP, ∠MNP = 90˚, seg NQ ⊥ seg MP, MQ = 9, QP = 4, find NQ.
In a rectangle ABCD,
prove that: AC2 + BD2 = AB2 + BC2 + CD2 + DA2.
Triangle XYZ is right-angled at vertex Z. Calculate the length of YZ, if XY = 13 cm and XZ = 12 cm.
Find the Pythagorean triplet from among the following set of numbers.
2, 4, 5
In the figure, find AR
In a quadrilateral ABCD, ∠A + ∠D = 90°. Prove that AC2 + BD2 = AD2 + BC2
[Hint: Produce AB and DC to meet at E.]
In an equilateral triangle PQR, prove that PS2 = 3(QS)2.
The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground. Find the length of the ladder.
