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प्रश्न
Integrate the following with respect to x.
`"e"^x [1/x^2 - 2/x^3]`
उत्तर
Letf(x) = `(-1)/x^2`
Then f'(x) = `(-2)/x^3`
So `int "e"^x [1/x^2 - 2/x^3] "d"x = int "e"^x ["f"(x) + "f'"(x)] "d"x`
= `"e"^x "f"(x) + "c"`
= `"e"^x/x^2 + "c"`
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