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प्रश्न
\[\lim_{x \to - 1} \frac{x^3 + 1}{x + 1}\]
उत्तर
\[\lim_{x \to - 1} \left[ \frac{x^3 + 1}{x + 1} \right]\]
\[ = \lim_{x \to - 1} \left[ \frac{x^3 - \left( - 1 \right)}{x - \left( - 1 \right)} \right]\]
\[ = \lim_{x \to - 1} \left[ \frac{x^3 - \left( - 1 \right)^3}{x - \left( - 1 \right)} \right]\]
\[ = 3 \left( - 1 \right)^{3 - 1} \]
\[ = 3\]
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