Advertisements
Advertisements
प्रश्न
Make x the subject of the formula y = `(1 - x^2)/(1 + x^2)`. Find x, when y = `(1)/(2)`
उत्तर
y = `(1 - x^2)/(1 + x^2)`
⇒ y(1 + x2) = 1 - x2
⇒ y + yx2 = 1 - x2
⇒ yx2 + x2 = 1 - y
⇒ x2( 1 + y) = 1 - y
⇒ x2 = `(1 - y)/(1 + y)`
⇒ x = `sqrt((1 - y)/(1 + y)`
Substituting y = `(1)/(2)`, we get
x = `sqrt((1 - 1/2)/(1 + 1/2)`
= `sqrt(1/3)`.
APPEARS IN
संबंधित प्रश्न
The arithmetic mean M of the five numbers a, b, c, d, e is equal to their sum divided by the number of quantities. Express it as a formula.
Make a the subject of formula S = `"ut" + (1)/(2)"at"^2`
Make d the subject of formula S = `"n"/(2){2"a" + ("n" - 1)"d"}`
If 3ax + 2b2 = 3bx + 2a2, then express x in terms of a and b. Also, express the result in the simplest form.
If b = `(2"a")/("a" - 2)`, and c = `(4"b" - 3)/(3"b" + 4)`, then express c in terms of a.
Make s the subject of the formula v2 = u2 + 2as. Find s when u = 3, a = 2 and v = 5.
Make y the subject of the formula `x/"a" + y/"b" `= 1. Find y, when a = 2, b = 8 and x = 5.
Make I the subject of the following M = `"L" /"F"(1/2"N" - "C") xx "I"`. Find I, If M = 44, L = 20, F = 15, N = 50 and C = 13.
The total energy E possess by a body of Mass 'm', moving with a velocity 'v' at a height 'h' is given by: E = `(1)/(2) "m" "u"^2 + "mgh"`. Make 'm' the subject of formula.
"Area A oof a circular ring formed by 2 concentric circles is equal to the product of pie and the difference of the square of the bigger radius R and the square of the bigger radius R and the square of the smaller radius r. Express the above statement as a formula. Make r the subject of the formula and find r, when A = 88 sq cm and R = 8cm.